quickjson json 解析框架 项目简介
quickjson目前版本1.0,大小1.48kb,相对于其他java解析json框架,具有以下特征:解析速度快json对象转换成java对象和键值对,json数组转换成java数组无需依赖其他jar,本身很小,几乎可以忽略无异常抛出示例:public class QuickJsonTest {
@Test
public void test1() {
JSONObject jsonObject = (JSONObject) JSON.parse("{\"array\":[1,2,3],\"boolean\":true,\"null\":null,\"number\":123,\"object\":{\"a\":\"b\",\"c\":\"d\",\"e\":\"f\"},\"string\":\"Hello World\"}");
System.out.println(jsonObject.getStringValue("string"));
System.out.println(jsonObject.getJSONObject("string"));
}
@Test
public void test2() {
System.out.println(JSON.parse("{\"name\":\"Tom\",\"age\":10,\"address\":\"anhui hfei\"}", A.class));
System.out.println(JSON.parseJSONObject("{\"name\":\"Tom\",\"age\":10,\"address\":\"anhui hfei\"}").toPojo(A.class));
System.out.println(JSON.parseJSONArray("[{\"name\":\"Tom\",\"age\":10,\"address\":\"anhui hfei\"}]").getPojoValue(0, A.class));
}
@Test
public void test3() {
System.out.println(JSON.toJSONString(new A("Tom", 11, "anhui hefei")));
System.out.println(JSON.toJSONString(new int[]{10,10,102,200}));
HashMap<String, Object> map = new HashMap<String,Object>();
map.put("name", "Tom");
map.put("age",11);
map.put("address", "anhui hefei");
System.out.println(JSON.toJSONString(map));
List<String> list = new ArrayList<String>();
list.add("Tom");
list.add("jack");
System.out.println(JSON.toJSONString(list));
}
}
@Test
public void test1() {
JSONObject jsonObject = (JSONObject) JSON.parse("{\"array\":[1,2,3],\"boolean\":true,\"null\":null,\"number\":123,\"object\":{\"a\":\"b\",\"c\":\"d\",\"e\":\"f\"},\"string\":\"Hello World\"}");
System.out.println(jsonObject.getStringValue("string"));
System.out.println(jsonObject.getJSONObject("string"));
}
@Test
public void test2() {
System.out.println(JSON.parse("{\"name\":\"Tom\",\"age\":10,\"address\":\"anhui hfei\"}", A.class));
System.out.println(JSON.parseJSONObject("{\"name\":\"Tom\",\"age\":10,\"address\":\"anhui hfei\"}").toPojo(A.class));
System.out.println(JSON.parseJSONArray("[{\"name\":\"Tom\",\"age\":10,\"address\":\"anhui hfei\"}]").getPojoValue(0, A.class));
}
@Test
public void test3() {
System.out.println(JSON.toJSONString(new A("Tom", 11, "anhui hefei")));
System.out.println(JSON.toJSONString(new int[]{10,10,102,200}));
HashMap<String, Object> map = new HashMap<String,Object>();
map.put("name", "Tom");
map.put("age",11);
map.put("address", "anhui hefei");
System.out.println(JSON.toJSONString(map));
List<String> list = new ArrayList<String>();
list.add("Tom");
list.add("jack");
System.out.println(JSON.toJSONString(list));
}
}