python实现简单登陆流程的方法
登陆流程图:
代码实现:
#-*- coding=utf-8 -*- import os,sys,getpass ''' user.txt 格式 账号 密码 是否锁定 错误次数 jack 123 unlock 0 tom 123 unlock 0 lily 123 unlock 0 hanmeimei 123 unlock 0 lucy 123 unlock 0 ''' # 定义写入文件的函数 def wirte_to_user_file(users,user_file_path): user_file = file(user_file_path,'w+') for k,v in users.items(): line = [] line.append(k) line.extend(v) user_file.write(' '.join(line)+'\n') user_file.close() # 判断用户文件是否存在,不存在直接退出 user_file_path = 'users.txt' if os.path.exists(user_file_path): user_file = file(user_file_path,'r') else: print 'user file is not exists' sys.exit(1) # 遍历用户文件,将用户包装成字典 users_dic = {} for user_line in user_file: user = user_line.strip().split() users_dic[user[0]] = user[1:] ''' { 'lucy': ['123', 'unlock', '0'], 'lily': ['123', 'unlock', '0'], 'jack': ['123', 'unlock', '0'], 'hanmeimei': ['123', 'unlock', '0'], 'tom': ['123', 'unlock', '0'] } ''' while True: # 输入账号 input_name = raw_input('please input your username,input "quit" or "q" will be exit : ').strip() # 判断是否为退出 if input_name == 'quit' or input_name == 'q': sys.exit(0) # 输入密码 password = getpass.getpass('please input your password:').strip() # 判断账号是否存在、是否锁定 if input_name not in users_dic: print 'username or password is not right' break if users_dic[input_name][1] == 'lock': print 'user has been locked' break # 判断密码是否正确,正确,登陆成功 if str(password) == users_dic[input_name][0]: print 'login success,welcome to study system' sys.exit(0) else: # 如果密码错误则修改密码错误次数 users_dic[input_name][2] = str(int(users_dic[input_name][2])+1) # 密码错误次数大于3的时候则锁定,并修改状态 if int(users_dic[input_name][2]) >= 3: print 'password input wrong has 3 times,user will be locked,please connect administrator' users_dic[input_name][1] = 'lock' wirte_to_user_file(users_dic,user_file_path) break wirte_to_user_file(users_dic,user_file_path)
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