jquery 中post 、get的同步问题
解决方法1:
在全局设置:
$.ajaxSetup({
async : false
}); 然后再使用post或get方法
$.get("register/RegisterState", {test : 12}, function(data, status) {
if (status == "success") {
data = eval("(" + data + ")");
aDataSet = data;
alert("data is " + aDataSet);
} else {
alert("wrong");
}
});解决方法2:
直接使用$.ajax,如
$.ajax({
type : "post",
url : "register/RegisterState",
data : "test=" + test,
async : false,
success : function(data){
data = eval("(" + data + ")");
aDataSet = data;
}
}); 相关推荐
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