用C语言在Linux下获取鼠标光标的相对位置
用C语言在Linux下获取鼠标光标的相对位置代码分享:
- #include <stdio.h>
- #include <stdlib.h>
- #include <linux/input.h>
- #include <fcntl.h>
- #include <sys/time.h>
- #include <sys/types.h>
- #include <sys/stat.h>
- #include <unistd.h>
- int main(int argc,char **argv)
- {
- int fd, retval;
- char buf[6];
- fd_set readfds;
- struct timeval tv;
- //fd = open("/dev/input/mice", O_RDONLY);
- if(( fd = open("/dev/input/mice", O_RDONLY))<0)
- {
- printf("Failed to open \"/dev/input/mice\".\n");
- exit(1);
- }
- else
- {
- printf("open \"/dev/input/mice\" successfuly.\n");
- }
- while(1)
- {
- tv.tv_sec = 5;
- tv.tv_usec = 0;
- FD_ZERO(&readfds);
- FD_SET(fd, &readfds);
- retval = select(fd+1, &readfds, NULL, NULL, &tv);
- if(retval==0)
- printf("Time out!\n");
- if(FD_ISSET(fd,&readfds))
- {
- if(read(fd, buf, 6) <= 0)//终端设备,一次只能读取一行
- {
- continue;
- }
- printf("Button type = %d, X = %d, Y = %d, Z = %d\n", (buf[0] & 0x07), buf[1], buf[2], buf[3]);
- }
- }
- close(fd);
- return 0;
- }
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