用 150 行 Python 代码写的量子计算模拟器
简评:让你更轻松地明白,量子计算机如何遵循线性代数计算的。
这是个 GItHub 项目,可以简单了解一下。
qusim.py 是一个多量子位的量子计算机模拟器(玩具?),用 150 行的 python 所编写。
这段代码可以让你轻松了解量子计算机如何遵循线性代数来计算的!
from QuSim import QuantumRegister ############################################# # Introduction # ############################################# # Here Will Be A Few Example of Different # # Quantum States / Algorithms, So You Can # # Get A Feel For How The Module Works, and # # Some Algorithmic Ideas # ############################################# ############################################# # Quantum Measurement # ############################################# # This experiment will prepare 2 states, of a # Single qubit, and of 5 qubits, and will just # Measure them OneQubit = QuantumRegister(1) # New Quantum Register of 1 Qubit print('One Qubit: ' + OneQubit.measure()) # Should Print 'One Qubit: 0' FiveQubits = QuantumRegister(5) # New Quantum Register of 5 Qubits # Should Print 'Five Qubits: 00000' print('Five Qubits: ' + FiveQubits.measure()) ############################################# # Swap 2 Qubits # ############################################# # Here, We Will Apply a Pauli-X Gate / NOT Gate # To the first qubit, and then after the algorithm, # it will be swapped to the second qubit. Swap = QuantumRegister(2) # New Quantum Register of 2 qubits Swap.applyGate('X', 1) # Apply The NOT Gate. If Measured Now, it should be 10 # Start the swap algorithm Swap.applyGate('CNOT', 1, 2) Swap.applyGate('H', 1) Swap.applyGate('H', 2) Swap.applyGate('CNOT', 1, 2) Swap.applyGate('H', 1) Swap.applyGate('H', 2) Swap.applyGate('CNOT', 1, 2) # End the swap algorithm print('SWAP: |' + Swap.measure() + '>') # Measure the State, Should be 01 ############################################# # Fair Coin Flip # ############################################# # Shown in this 'Experiment', is a so called 'Fair Coin Flip', # Where a state will be prepared, that has an equal chance of # Flipping to Each Possible State. to do this, the Hadamard # Gate will be used. # New Quantum Register of 1 Qubit (As a coin has only 2 states) FairCoinFlip = QuantumRegister(1) # If measured at this point, it should be |0> # Apply the hadamard gate, now theres an even chance of measuring 0 or 1 FairCoinFlip.applyGate('H', 1) # Now, the state will be measured, flipping the state to # either 0 or 1. If its 0, we will say "Heads", or if its # 1, we will say "Tails" FairCoinFlipAnswer = FairCoinFlip.measure() # Now its flipped, so we can test if FairCoinFlipAnswer == '0': print('FairCoinFlip: Heads') elif FairCoinFlipAnswer == '1': print('FairCoinFlip: Tails') ############################################# # CNOT Gate # ############################################# # In this experiment, 4 states will be prepared, {00, 01, 10, 11} # And then the same CNOT Gate will be run on them, # To Show The Effects of the CNOT. The Target Qubit will be 2, and the control 1 # New Quantum Register of 2 Qubits, done 4 times. # If any are measured at this time, the result will be 00 ZeroZero = QuantumRegister(2) ZeroOne = QuantumRegister(2) OneZero = QuantumRegister(2) OneOne = QuantumRegister(2) # Now prepare Each Into The State Based On Their Name # ZeroZero Will be left, as thats the first state anyway ZeroOne.applyGate('X', 2) OneZero.applyGate('X', 1) OneOne.applyGate('X', 1) OneOne.applyGate('X', 2) # Now, a CNOT Will Be Applied To Each. ZeroZero.applyGate('CNOT', 1, 2) ZeroOne.applyGate('CNOT', 1, 2) OneZero.applyGate('CNOT', 1, 2) OneOne.applyGate('CNOT', 1, 2) # Print the results. print('CNOT on 00: |' + ZeroZero.measure() + '>') print('CNOT on 01: |' + ZeroOne.measure() + '>') print('CNOT on 10: |' + OneZero.measure() + '>') print('CNOT on 11: |' + OneOne.measure() + '>')
主要代码来自:corbett/QuantumComputing.
如果你对用 RUST 所写的高效、高性能的硬件量子计算模拟器有兴趣,可以点击 QCGPU 来查看更多内容。
GITHUB 地址:adamisntdead/QuSimPy相关推荐
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