字符串中的第一个唯一字符 python

给定一个字符串，找到它的第一个不重复的字符，并返回它的索引。如果不存在，则返回 -1。

s = "leetcode"
返回 0.

s = "loveleetcode",
返回 2.

class solution:    def getChar(self,s):        setS = set(s)        dict = {}        for i in setS:            dict[i] = s.count(i)     #该方法返回子字符串在字符串中出现的次数。        for index,value in enumerate(s):            print(‘j‘+str(index)+‘ , k‘+str(value))            if dict.get(value) == 1:                return index        return -1    def getChar2(self,s):        return min([s.find(c) for c in ‘abcdefghijklmnopqrstuvwxyz‘ if s.count(c)==1] or [-1])if __name__ == "__main__":    solution = solution()    index = solution.getChar(‘leetcode‘)    index2 = solution.getChar(‘loveleetcode‘)    print(index)    print(index2)    print(solution.getChar2(‘leetcode‘))    print(solution.getChar2(‘loveleetcode‘))