python去除扩展名的实例讲解
获取不带扩展名的文件的名称:
import os printos.path.splitext("path_to_file")[0] from os.path import basename # now you can call it directly with basename print basename("/a/b/c.txt") >>>base=os.path.basename('/root/dir/sub/file.ext') >>> base 'file.ext' >>> os.path.splitext(base) ('file', '.ext') >>> os.path.splitext(base)[0] 'file' >>> >>> printos.path.splitext(os.path.basename("hemanth.txt"))[0] hemanth >>> file ='/root/dir/sub.exten/file.data.1.2.dat' >>> print('.').join(file.split('.')[:-1]) /root/dir/sub.exten/file.data.1.2 >>> s = 'c:\\temp\\akarmi.txt' >>> print(os.path.splitext(s)[0]) c:\temp\akarmi 因此,我不需要驱动器号或者目录名,我使用: >>>print(os.path.splitext(os.path.basename(s))[0]) akarmi def getFileNameWithoutExtension(path): returnpath.split('\\').pop().split('/').pop().rsplit('.', 1)[0] getFileNameWithoutExtension('/path/to/file-0.0.1.ext') # => file-0.0.1 getFileNameWithoutExtension('\\path\\to\\file-0.0.1.ext') # => file-0.0.1
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