php实现查询功能（数据访问）
本文实例为大家分享了php实现查询功能的具体代码，供大家参考，具体内容如下
输入关键字效果
代码：
<body>
<h1>汽车信息</h1>
<?php
require"DBDA.class1.php";//$type 代表SQL语句的类型，0代表增删改，1代表查询
$db = new DBDA();
//如果没有提交数据，显示所有
//如果有提交数据，根据关键字查询显示
$name = "";
$tj1 = " 1=1 ";//第一个条件，对应名称，注意空格
$tj2 = " 1=1 ";//第二个条件，对应系列，注意空格
if(!empty($_POST["name"]))
{
$name = $_POST["name"];
$tj1 = " name like '%{$name}%'";
}
if(!empty($_POST["brand"]))
{
$brand = $_POST["brand"];
$tj2 = " brand like '%{$brand}%'";
}
//总条件
$tj ="{$tj1} and {$tj2}";
$sql = "select * from car where ".$tj;//注意where后空格
/*echo $sql;*/
?>
<form action="chaxun.php" method="post">
<div>名称：<input type="text" name="name" value="<?php echo $name ?>"/>系列：<input type="text" name="brand"/><input type="submit" value="查询" /></div>
</form>
<br/>
<table width="100%" border="1" cellpadding="0" cellspacing="0">
<tr>
<td>代号</td>
<td>名称</td>
<td>系列</td>
<td>上市时间</td>
<td>价格</td>
</tr>
<?php
//只适用于单条件查询
/*$sql = "select * from car";
$name="";
if(!empty($_POST["name"]))
{
$name = $_POST["name"];
$sql = "select * from car where name like '%{$name}%' ";
}*/
$arr = $db->query($sql);
foreach($arr as $v)
{
$str = str_replace($name,"<span style='color:red'>{$name}</span>",$v[1]);
echo "<tr>
<td>{$v[0]}</td>
<td>{$str}</td>
<td>{$v[2]}</td>
<td>{$v[3]}</td>
<td>{$v[7]}</td>
</tr>";
}
?>
</table>
</body>
</html>所引用的封装类
<?php
class DBDA
{
public $host = "localhost";
public $uid = "root";
public $pwd = "123";
public $dbname = "newssystem";
//执行SQL语句返回相应的结果
//$sql 要执行的SQL语句
//$type 代表SQL语句的类型，0代表增删改，1代表查询
function query($sql,$type=1)
{
$db = new MySQLi($this->host,$this->uid,$this->pwd,$this->dbname);
$result = $db->query($sql);
if($type)
{
//如果是查询，显示数据
return $result->fetch_all();
}
else
{
//如果是增删改，返回true或者false
return $result;
}
}
}以上就是本文的全部内容，希望对大家的学习有所帮助，也希望大家多多支持安科网。
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