R语言学习笔记(二十一):字符串处理中的元字符
元字符有自己的特殊含义
states <- row.names(USArrests) # 提取字符串子集 substr(x = states, start = 1, stop = 4) abbreviate(states, minlength = 5) # 计算字符串长度 state_chars <- nchar(states) # 字符串匹配 grep(pattern = "w", x = states, value = T) # 匹配大写和小写
[ ]内的任意字符将被匹配
grep(pattern = "[wW]", x = states, value = T)
grep(pattern = "w", ignore.case = T, x = states, value = T)
tolower(states) # 变为小写
toupper(states) # 变为大写
library("stringr")
# 含a的数目
str_count(states, "a")\对元字符进行转义
strsplit("strsplit.also.uses", split = ".")
strsplit("strsplit.also.uses", split = "\\.")
str_extract_all("me credit card: 334", pattern = "\\d")^匹配字符串的开头,将^置于character class 的首位表达的意思是取反义。如[ˆ5] 表示匹配除了“5” 以外的所有字符。
test_vector <- c("123","456","321")
str_extract_all(test_vector, "3")
str_extract_all(test_vector, "^3")
str_extract_all(test_vector, "[^3]")$匹配字符串的结尾。但将它置于character class 内则消除了它的特殊含义。如[akm$]将匹配'a','k','m' 或者'$'。
str_extract_all(test_vector, "3$") str_extract_all(test_vector, "[3$]")
.匹配除换行符以外的任意字符。
str_extract_all(string = c("regular.exp\n","\n"), pattern =".")|或者
str_extract_all(string = "we23", pattern ="b|w|3")
?此符号前的字符(组) 是可有可无的,并且最多被匹配一次
str_extract_all(string = c("abc","bc","ac"),pattern = "ab?c")( )表示一个字符组,括号内的字符串将作为一个整体被匹配
str_extract_all(string = c("abc","ac","cde"),pattern = "(ab)c")*此符号前的字符(组) 将被匹配零次或多次
str_extract_all(string = c("abab","abc","ac"),pattern = "(ab)*")+前面的字符(组) 将被匹配一次或多次
str_extract_all(string = c("abbab","abc","ac"),pattern = "ab+"){n,m}重复n次到m次
str_extract_all(string = c("abababab","ababc","abc"),pattern = "(ab){2}")
str_extract_all(string = c("abababab","ababc","abc"),pattern = "(ab){2,}")
str_extract_all(string = c("abababab","ababc","abc"),pattern = "(ab){2,3}") 相关推荐
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