asp.net 将图片上传到mysql数据库的方法
这是页面上的按钮单击事件
这是执行插入的方法
代码如下:
protected void Button1_Click(object sender, EventArgs e) { string tid = Utils.getRandom(32); Stream mystream = this.FileUpload1.PostedFile.InputStream; int length = this.FileUpload1.PostedFile.ContentLength; byte[] pic = new byte[length]; mystream.Read(pic, 0, length); bool flg = insert(tid, pic); }
这是执行插入的方法
代码如下:
public bool insert(string tid,byte[] pic) { DBConn db = new DBConn(); StringBuilder sql = new StringBuilder(); sql.Append("insert into teacher(TID,TPHOTO,TDELETE) values (?tid,?pic,?flg)"); int flg = 0; try { myConnection = db.getConnection(); MySqlCommand myCommand = new MySqlCommand(sql.ToString(), myConnection); myCommand.Parameters.Add(new MySqlParameter("?tid", MySqlDbType.String, 32)); myCommand.Parameters["?tid"].Value = tid; myCommand.Parameters.Add(new MySqlParameter("?pic", MySqlDbType.Blob)); myCommand.Parameters["?pic"].Value = pic; myCommand.Parameters.Add(new MySqlParameter("?flg", MySqlDbType.Int16)); myCommand.Parameters["?flg"].Value = 0; myConnection.Open(); flg = myCommand.ExecuteNonQuery(); } catch (Exception ex) { return false; } finally { if (myConnection != null) { myConnection.Close(); } } if (flg > 0) { return true; } return false; }
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