手机通讯录联系人搜索

1.需求：

2.实现原理

3.正则表达式

^(.*\\b)?$1.*$

4.测试

static String sourceStr = "YAO 姚 YI 亦 RONG 容";

static String key = "YI";

static String reg = "(.*\\b)?$1";

// TODO 优化：charAt()效率，StringBuffer
public static void main(String[] args) {
    String regex = "";
    key = key.toUpperCase();
    for (int i = 0; i < key.length(); i++) {
        regex += reg.replace("$1", String.valueOf(key.charAt(i)));
    }
    regex = "^" + regex + ".*$";
    System.out.println(regex);
        System.out.println(Pattern.compile(regex).matcher(sourceStr).matches());
}