剑指offer反转链表python
题目描述
输入一个链表,反转链表后,输出新链表的表头。
思路
定义三个指针,pHead, cur,forward
反转的时候,cur.next指向pHead,然后三个指针依次向后移动,具体过程看代码。
代码
# -*- coding:utf-8 -*- # class ListNode: # def __init__(self, x): # self.val = x # self.next = None class Solution: # 返回ListNode def ReverseList(self, pHead): # write code here if not pHead or not pHead.next: return pHead current = pHead.next forward = current.next pHead.next = None while current: current.next = pHead pHead = current current = forward if forward: forward = forward.next return pHead
相关推荐
koushr 2020-11-12
范范 2020-10-28
zhaochen00 2020-10-13
Mars的自语 2020-09-27
steeven 2020-09-18
kka 2020-09-14
qiangde 2020-09-13
聚沙成塔积水成渊 2020-08-16
earthhouge 2020-08-15
aanndd 2020-08-12
范范 2020-07-30
bluetears 2020-07-28
mingyunxiaohai 2020-07-19
horizonheart 2020-07-19
liushall 2020-07-18
bluetears 2020-07-05
fengshantao 2020-07-02
liuweixiao0 2020-06-27