Lua编程示例(六): C语言调用Lua函数
C++端:
#include "stdafx.h" lua_State *L; void load_lua(lua_State **L,char *filename){ *L=luaL_newstate(); luaL_openlibs(*L); if(luaL_loadfile(*L,filename) || lua_pcall(*L,0,0,0)){ luaL_error(*L,"load file error! %s",lua_tostring(*L,-1)); } } int _tmain(int argc, _TCHAR* argv[]) { load_lua(&L,"raw.lua"); //此处若直接传入L会出错 lua_getglobal(L,"gettable"); if(lua_pcall(L,0,1,0) !=0){ luaL_error(L,"pcall wrong %s",lua_tostring(L,-1)); } luaL_checktype(L,1,LUA_TTABLE); int n=lua_objlen(L,1); printf("n = %d\n",n); lua_pushstring(L,"ee"); lua_rawseti(L,1,5); //t[n]=v,n为第三个参数,v是栈顶元素 n=lua_objlen(L,1); printf("n = %d\n",n); int i; for(i=1;i<=n;i++){ lua_rawgeti(L,1,i); printf("%s\n",lua_tostring(L,-1)); } return 0; }
lua脚本:
function gettable() tb={ "aa","bb","cc","dd"} return tb end
运行输出的结果为:
n = 4 n = 5 aa bb cc dd ee
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