jQuery实现两个select控件的互移操作
一、直接上代码
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8" />
<title>index</title>
</head>
<body>
<div>
<select id="leftSelector" multiple="multiple" name="SmsListOnLeft" style="height:100px; width:50px">
<option value="0">0</option>
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
<option value="4">4</option>
<option value="5">5</option>
</select>
<span style="top: 30px; position: fixed;">
<input type="button" value="<<" id="btnLeft" />
<input type="button" value=">>" id="btnRight" />
</span>
<select id="rightSelector" multiple="multiple" name="SmsListOnRight" style="height:100px; width:50px; margin-left:80px">
<option value="6">A</option>
<option value="7">B</option>
<option value="8">C</option>
<option value="9">D</option>
<option value="10">E</option>
</select>
</div>
<br>
<input type="button" onclick="selectAll()" id="btnSelectAll" value="selectAll" />
<script src="js/jquery-2.1.4.js"></script>
<script>
$("#btnRight").click(function () {
//数据option选中的数据集合赋值给变量vSelect
var vSelect = $("#leftSelector option:selected");
//克隆数据添加到 rightSelector 中
vSelect.clone().appendTo("#rightSelector");
//同时移除 leftSelector 中的 option
vSelect.remove();
});
//right move
$("#btnLeft").click(function () {
var vSelect = $("#rightSelector option:selected");
vSelect.clone().appendTo("#leftSelector");
vSelect.remove();
});
function selectAll() {
var lst1 = window.document.getElementById("rightSelector");
var length = lst1.options.length;
for (var i = 0; i < length; i++) {
var v = lst1.options[i].value; //option内的value
var t = lst1.options[i].text; //显示的文本
alert(v + ":" + t);
}
}
</script>
</body>
</html>二、效果图
相关推荐
专注前端开发 2020-10-21
苏康申 2020-11-13
vitasfly 2020-11-12
oraclemch 2020-11-06
liuyang000 2020-09-25
FellowYourHeart 2020-10-05
赵继业 2020-08-17
whyname 2020-08-16
Seandba 2020-08-16
dbasunny 2020-08-16
拼命工作好好玩 2020-08-15
langyue 2020-08-15
写程序的赵童鞋 2020-08-03
Accpcjg 2020-08-02
tydldd 2020-07-30
好记忆也需烂 2020-07-28
jianghero 2020-07-28