python抓取网页中链接的静态图片
本文实例为大家分享了python抓取网页中链接的静态图片的具体代码,供大家参考,具体内容如下
# -*- coding:utf-8 -*- #http://tieba.baidu.com/p/2460150866 #抓取图片地址 from bs4 import BeautifulSoup import urllib.request from time import sleep html_doc = "http://tieba.baidu.com/p/2460150866" def get_image(url): req = urllib.request.Request(url) webpage = urllib.request.urlopen(req) html = webpage.read() soup = BeautifulSoup(html, 'html.parser') #抓取图片地址 #抓取img标签且class为BDE_Image的所有内容 img_src=soup.findAll("img",{'class':'BDE_Image'}) i = 1 for img in img_src: img_url = img.get('src') #抓取src # print(img) req = urllib.request.Request(img_url) u = urllib.request.urlopen(req) data = u.read() with open("AutoCodePng20180119-"+str(i)+".jpg", 'wb') as f: sleep(2) f.write(data) i += 1 def getImg(url): html = urllib.request(url) page = html.read() soup = BeautifulSoup(page, "html.parser") imglist = soup.find_all('img') #发现html中带img标签的数据,输出格式为<img xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx,存入集合 lenth = len(imglist) #计算集合的个数 for i in range(lenth): print imglist[i].attrs['src'] #抓取img中属性为src的信息,例如<img src="123456" xxxxxxxxxxxxxxxx,则输出为123456
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