利用Python为iOS10生成图标和截屏

adamlovejw

2019-04-25

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简介

这两天更新完Xcode8之后发现Xcode对图标的要求又有了变化，之前用的一个小应用“IconKit”还没赶上节奏，已经不能满足Xcode8的要求了。

于是就想起来用Python自己做个脚本来生成图标。

其实这个脚本很早就写了，现在为了适应iOS10，就修改完善下，并且放到了GitHub。

可以看看效果图：

1.png

代码：

#encoding=utf-8
#by 不灭的小灯灯
#create date 2016/5/22
#update 2016/9/21
#support iOS 10
#site www.winterfeel.com
import os
import sys
from PIL import Image
 
iosSizes = ['20@1x','20@2x','20@3x','29@1x','29@2x','29@3x','40@1x','40@2x','40@3x','60@2x','60@3x','60@3x','76@1x','76@2x','167@1x']
androidSizes = [32,48,72,96,144,192]
androidNames = ['ldpi','mdpi','hdpi','xhdpi','xxhdpi','xxxhdpi']
 
sizesiOS = [(640,960),(640, 1136),(750, 1334),(1242, 2208),(1536, 2048),(2048, 2732)]
foldersiOS = ['iPhone4s','iPhone5','iPhone6','iPhone6plus','iPad','iPadLarge']
 
sizesAndroid = [(480,800),(720,1280),(1080,1920)]
foldersAndroid = ['480x800','720x1280','1080x1920']
 
def processIcon(filename,platform):
  icon = Image.open(filename).convert("RGBA")
  if icon.size[0] != icon.size[1]:
    print 'Icon file must be a rectangle!'
    return
  if platform == 'android':
    #安卓圆角
    mask = Image.open('mask.png')
    r,g,b,a = mask.split()
    icon.putalpha(a)
    if not os.path.isdir('androidIcon'):
      os.mkdir('androidIcon')
    index = 0
    for size in androidSizes:
      im = icon.resize((size,size),Image.BILINEAR)
      im.save('androidIcon/icon-'+ androidNames[index]+'.png')
      index = index + 1
  else:
    if not os.path.isdir('iosIcon'):
      os.mkdir('iosIcon')
    for size in iosSizes:
      originalSize = int(size.split('@')[0])#原始尺寸
      multiply = int(size.split('@')[1][0:1])#倍数
      im = icon.resize((originalSize*multiply,originalSize*multiply),Image.BILINEAR)
      im.save('iosIcon/icon'+size+'.png')
  print 'Congratulations!It\'s all done!'
 
def walk_dir(dir,platform):
  files = os.listdir(dir)
  for name in files:
    if name.split('.')[-1] == 'jpg' or name.split('.')[-1] == 'png':#处理jpg和png
      produceImage(name,platform)
  print 'Congratulations!It\'s all done!'
 
def produceImage(filename,platform):
  print 'Processing:' + filename
  img = Image.open(filename)
  index = 0
  sizes = sizesiOS
  folders = foldersiOS
  if platform == 'android':#默认ios，如果是安卓
    sizes = sizesAndroid
    folders = foldersAndroid
  for size in sizes:
    if not os.path.isdir(folders[index]):
      os.mkdir(folders[index])
    if img.size[0] > img.size[1]:#如果是横屏，交换坐标
      im = img.resize((size[1],size[0]),Image.BILINEAR)
      im.save(folders[index]+'/'+filename)
    else:
      im = img.resize(size,Image.BILINEAR)
      im.save(folders[index]+'/'+filename)
    index = index + 1
 
action = sys.argv[1]#action:icon or screenshot
if action == 'screenshot':  
  platform = sys.argv[2]#platform
  if platform == 'ios':
    walk_dir('./','ios')
  elif platform == 'android':
    walk_dir('./','android')
  else:
    print 'Hey,Platform can only be "ios" or "android" !'
elif action == 'icon':
  filename = sys.argv[2]#image filename
  platform = sys.argv[3]#platform
  if not os.path.exists(filename):
    print 'Hey,File Not Found!'
  else:
    if platform == 'ios':
      processIcon(filename,'ios')
    elif platform == 'android':
      processIcon(filename,'android')
    else:
      print 'Hey,Platform can only be "ios" or "android" !'
else:
  print 'Hey,action can only be "icon" or "screenshot" !'

脚本环境要求

Python 2.7

PIL or Pillow

笔者亲测，也许是笔者太菜，试了各种方法安装PIL总是出错，最后还是用了Pillow，效果一样的。

怎么使用脚本

在Windows的命令行或者Mac的终端，输入:

python tool.py [action] [filename] [platform]
action：icon 或者 screenshot
filename：图标文件名，截屏不需要文件名，自动遍历
platform：ios 或者 android

举一些例子：

生成iOS的图标：python tool.py icon icon.jpg ios

生成安卓的图标：python tool.py icon icon.jpg android

生成iOS的截屏：python tool.py screenshot ios

生成安卓的截屏：python tool.py screenshot android