Jquery实现上下移动和排序代码
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下文为大家介绍下Jquery实现上下移动和排序,感兴趣的朋友可以了解一下。
解决问题
代码实现:
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title>Insert title here</title> </head> <script type="text/javascript" src="jquery-2.0.0.js"></script> <!-- <script type="text/javascript" src="resource_demo.js"></script> <script type="text/javascript" src="jquery.alerts.js"></script> <script type="text/javascript" src="ztree/js/jquery.ztree.js"></script> <script type="text/javascript" src="ztree/css/zTreeStyle/zTreeStyle.css"></script> <script type="text/javascript"src="jBox/jBox/jquery-1.4.2.min.js"></script> <script type="text/javascript"src="jBox/jBox/jquery.jBox-2.3.min.js"></script> <script type="text/javascript"src="jBox/jBox/i18n/jquery.jBox-zh-CN.js"></script> <script type="text/javascript"src="jquery.cookie.js"></script> <link href="jBox/jBox/Skins/Blue/jbox.css" rel="stylesheet" type="text/css" /> --> <body> <div id="checkAndInverCheck"> <table style="align:center"> <tr> <td><input type="checkbox" value="蕙兰">蕙兰</td> <td><input type="text" name="orderNum" size="3" value="1"/></td> <td><input type="button" name="upMove" value="上移"/></td> <td><input type="button" name="downMove" value="下移"/></td> </tr> <tr> <td><input type="checkbox" value="建兰">建兰</td> <td><input type="text" name="orderNum" size="3" value="2"/></td> <td><input type="button" name="upMove" value="上移"/></td> <td><input type="button" name="downMove" value="下移"/></td> </tr> <tr> <td><input type="checkbox" value="寒兰">寒兰</td> <td><input type="text" name="orderNum" size="3" value="3"/></td> <td><input type="button" name="upMove" value="上移"/></td> <td><input type="button" name="downMove" value="下移"/></td> </tr> <tr> <td><input type="checkbox" value="墨兰">墨兰</td> <td><input type="text" name="orderNum" size="3" value="4"/></td> <td><input type="button" name="upMove" value="上移"/></td> <td><input type="button" name="downMove" value="下移"/></td> </tr> </div> <script type="text/javascript"> //上移 $("input[name='upMove']").bind("click",function(){ var $this = $(this); var curTr = $this.parents("tr"); var prevTr = $this.parents("tr").prev(); if(prevTr.length == 0){ alert("第一行,想移啥?"); return; }else{ prevTr.before(curTr); sortNumber();//重新排序 } }); //下移 $("input[name='downMove']").bind("click",function(){ var $this = $(this); var curTr = $this.parents("tr"); var nextTr = $this.parents("tr").next(); if(nextTr.length == 0){ alert("最后一行,想移啥?"); return; }else{ nextTr.after(curTr); sortNumber();//重新排序 } }); //排序 $("input[name='orderNum']").bind("change",function(){ var $this = $(this); //获得当前行 var curTr = $this.parents("tr"); var curOrderNum = $this.val(); //当前行同级的所有行 var siblingsTrs = curTr.siblings(); if(siblingsTrs.length >0){ for(var i in siblingsTrs){ var otherOrderNum = $(siblingsTrs[i]).children().find("input[name='orderNum']").val(); if(parseInt(curOrderNum) <= parseInt(otherOrderNum)){ $(siblingsTrs[i]).before(curTr); sortNumber();//重新排序 break; } } } }); function sortNumber(){ var allInput = $("#checkAndInverCheck").find("input[name='orderNum']"); alert(123); if(allInput.length != 0){ for(var i=0;i<allInput.length;i++){ var tempInput = allInput[i]; tempInput.value = i + 1; } } } </script> </body> </html>
效果如下:
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