Spring中的SpringUtils工具类
Spring中的SpringUtils
Spring提供的工具类,主要用于框架内部使用,这个类提供了一些简单的方法,并且提供了易于使用的方法在分割字符串,如CSV字符串,以及集合和数组。
StringUtils提供常用的方法如下:
判断对象对象是否为null或者空字符串
public static boolean isEmpty(@Nullable Object str) { return (str == null || "".equals(str)); }
判断给的序列是否为空或者length为0
public static boolean hasLength(@Nullable CharSequence str) { return (str != null && str.length() > 0); } public static boolean hasLength(@Nullable String str) { return (str != null && !str.isEmpty()); }
判断字符串是否以某个字符串开头
public static boolean startsWithIgnoreCase(@Nullable String str, @Nullable String prefix) { return (str != null && prefix != null && str.length() >= prefix.length() && str.regionMatches(true, 0, prefix, 0, prefix.length())); }
判断字符串是否以某个字符串结尾
public static boolean endsWithIgnoreCase(@Nullable String str, @Nullable String suffix) { return (str != null && suffix != null && str.length() >= suffix.length() && str.regionMatches(true, str.length() - suffix.length(), suffix, 0, suffix.length())); }
用另一个字符串替换字符串中出现的所有子字符串
public static String replace(String inString, String oldPattern, @Nullable String newPattern) { if (!hasLength(inString) || !hasLength(oldPattern) || newPattern == null) { return inString; } //oldPattern字符串第一次出现的位置 int index = inString.indexOf(oldPattern); if (index == -1) { // no occurrence -> can return input as-is return inString; } //字符串长度 int capacity = inString.length(); if (newPattern.length() > oldPattern.length()) { capacity += 16; } StringBuilder sb = new StringBuilder(capacity); int pos = 0; // our position in the old string int patLen = oldPattern.length(); while (index >= 0) { sb.append(inString, pos, index); sb.append(newPattern); pos = index + patLen; index = inString.indexOf(oldPattern, pos); } // append any characters to the right of a match sb.append(inString, pos, inString.length()); return sb.toString(); }
根据给定的路径规范化路径
public static String cleanPath(String path) { if (!hasLength(path)) { return path; } //用新字符串替换旧字符串 String pathToUse = replace(path, WINDOWS_FOLDER_SEPARATOR, FOLDER_SEPARATOR); // Shortcut if there is no work to do if (pathToUse.indexOf(‘.‘) == -1) { return pathToUse; } // Strip prefix from path to analyze, to not treat it as part of the // first path element. This is necessary to correctly parse paths like // "file:core/../core/io/Resource.class", where the ".." should just // strip the first "core" directory while keeping the "file:" prefix. int prefixIndex = pathToUse.indexOf(‘:‘); String prefix = ""; if (prefixIndex != -1) { prefix = pathToUse.substring(0, prefixIndex + 1); if (prefix.contains(FOLDER_SEPARATOR)) { prefix = ""; } else { pathToUse = pathToUse.substring(prefixIndex + 1); } } if (pathToUse.startsWith(FOLDER_SEPARATOR)) { prefix = prefix + FOLDER_SEPARATOR; pathToUse = pathToUse.substring(1); } String[] pathArray = delimitedListToStringArray(pathToUse, FOLDER_SEPARATOR); LinkedList<String> pathElements = new LinkedList<>(); int tops = 0; for (int i = pathArray.length - 1; i >= 0; i--) { String element = pathArray[i]; if (CURRENT_PATH.equals(element)) { // Points to current directory - drop it. } else if (TOP_PATH.equals(element)) { // Registering top path found. tops++; } else { if (tops > 0) { // Merging path element with element corresponding to top path. tops--; } else { // Normal path element found. pathElements.add(0, element); } } } // Remaining top paths need to be retained. for (int i = 0; i < tops; i++) { pathElements.add(0, TOP_PATH); } // If nothing else left, at least explicitly point to current path. if (pathElements.size() == 1 && "".equals(pathElements.getLast()) && !prefix.endsWith(FOLDER_SEPARATOR)) { pathElements.add(0, CURRENT_PATH); } return prefix + collectionToDelimitedString(pathElements, FOLDER_SEPARATOR); }