LinkedList源码分析
一、属性及获取属性:
1、size
transient int size = 0; /** * Pointer to first node. * Invariant: (first == null && last == null) || * (first.prev == null && first.item != null) */ transient Node<E> first; /** * Pointer to last node. * Invariant: (first == null && last == null) || * (last.next == null && last.item != null) */ transient Node<E> last;
获取
public int size() { return size; }
二、构造函数
//Constructs an empty list public LinkedList() { } public LinkedList(Collection<? extends E> c) { this(); addAll(c); }
三、类
private static class Node<E> { E item; Node<E> next; Node<E> prev; Node(Node<E> prev, E element, Node<E> next) { this.item = element; this.next = next; this.prev = prev; } }
四、方法
1、Node
Node<E> node(int index) { // assert isElementIndex(index); if (index < (size >> 1)) { Node<E> x = first; for (int i = 0; i < index; i++) x = x.next; return x; } else { Node<E> x = last; for (int i = size - 1; i > index; i--) x = x.prev; return x; } }
*、linkFirst
/** * Links e as first element. */ private void linkFirst(E e) { final Node<E> f = first; final Node<E> newNode = new Node<>(null, e, f); first = newNode; if (f == null) last = newNode; else f.prev = newNode; size++; modCount++; } void linkLast(E e) { final Node<E> l = last; final Node<E> newNode = new Node<>(l, e, null); last = newNode; if (l == null) first = newNode; else l.next = newNode; size++; modCount++; }
*、add、addFirst
public void addFirst(E e) { linkFirst(e); } public boolean add(E e) { linkLast(e); return true; }
linkLast
2、set
public E set(int index, E element) { checkElementIndex(index); Node<E> x = node(index); E oldVal = x.item; x.item = element; return oldVal; }
3、get
public E get(int index) { checkElementIndex(index); return node(index).item; }
*、clear
public void clear() { // Clearing all of the links between nodes is "unnecessary", but: // - helps a generational GC if the discarded nodes inhabit // more than one generation // - is sure to free memory even if there is a reachable Iterator for (Node<E> x = first; x != null; ) { Node<E> next = x.next; x.item = null; x.next = null; x.prev = null; x = next; } first = last = null; size = 0; modCount++; }
*、Push Pop
public void push(E e) { addFirst(e); }
public E pop() { return removeFirst(); }
*、node(int index)
Node<E> node(int index) { // assert isElementIndex(index); if (index < (size >> 1)) { Node<E> x = first; for (int i = 0; i < index; i++) x = x.next; return x; } else { Node<E> x = last; for (int i = size - 1; i > index; i--) x = x.prev; return x; } }
相关推荐
瓜牛呱呱 2020-11-12
柳木木的IT 2020-11-04
yifouhu 2020-11-02
lei0 2020-11-02
源码zanqunet 2020-10-28
源码zanqunet 2020-10-26
一叶梧桐 2020-10-14
码代码的陈同学 2020-10-14
lukezhong 2020-10-14
lzzyok 2020-10-10
anchongnanzi 2020-09-21
clh0 2020-09-18
changcongying 2020-09-17
星辰大海的路上 2020-09-13
abfdada 2020-08-26
mzy000 2020-08-24
shenlanse 2020-08-18
zhujiangtaotaise 2020-08-18
xiemanR 2020-08-17